Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

C-callback to function template: explicitly instantiate template

Premise

I’m using a C library (from C++) which provides the following interface:

void register_callback(void* f, void* data);
void invoke_callback();

Problem

Now, I need to register a function template as a callback and this is causing me problems. Consider the following code:

template <typename T> void my_callback(void* data) { … }

int main() {
    int ft = 42;
    register_callback(reinterpret_cast<void*>(&my_callback<int>), &ft);
    invoke_callback();
}

This gives me the following linker error (using g++ (GCC) 4.5.1 on OS X but works on most other combinations of compiler version / platform):

Undefined symbols for architecture x86_64:

"void my_callback<int>(void*)", referenced from:  
  _main in ccYLXc5w.o

which I find understandable.

First “solution”

This is easily fixed by explicitly instantiating the template:

template void my_callback<int>(void* data);

Unfortunately, this isn’t applicable in my real code since the callback is registered inside a function template, and I don’t know for which set of template arguments this function will be called, so I can’t provide explicit instantiations for all of them (I’m programming a library). So my real code looks a bit like this:

template <typename T>
void do_register_callback(T& value) {
    register_callback(reinterpret_cast<void*>(my_callback<T>), &value);
    // Other things …
}

int main() {
    int ft = 42;
    do_register_callback(ft);
    invoke_callback();
}

Second “solution”

A function template is implicitly instantiated by calling the function. So let’s do that, but make sure that the call isn’t actually performed (the function has got side-effects):

template <typename T>
void do_register_callback(T& value) {
    if (false) { my_callback<T>(0); }
    register_callback(reinterpret_cast<void*>(my_callback<T>), &value);
}

This seems to work, even with optimisations enabled (so that the dead branch is removed by the compiler). But I’m not sure if this won’t some day break down. I also find this a very ugly solution that requires a length explanatory comment lest some future maintainer remove this obviously unnecessary code.

Question

How do I instantiate a template for which I don’t know the template arguments? This question is obviously nonsense: I can’t. – But is there a sneaky way around this?

Barring that, is my workaround guaranteed to succeed?

Bonus question

The code (specifically, the fact that I cast a function pointer to void*) also produces the following warning:

ISO C++ forbids casting between pointer-to-function and pointer-to-object

when compiling with -pedantic. Can I somehow get rid of the warning, without writing a strongly-typed C wrapper for the library (which is impossible in my situation)?

Running code on ideone (with an added cast to make it compile)

like image 749
Konrad Rudolph Avatar asked Jul 18 '11 14:07

Konrad Rudolph


1 Answers

Apparently, the real problem was the missing static_cast in my original code:

register_callback(reinterpret_cast<void*>(&my_callback<int>), &ft);

This compiles fine, but triggers the liker error when using GCC 4.5. It doesn’t even compile when using GCC 4.2, instead giving the following compile error:

insufficient contextual information to determine type

Once this “contextual information” is provided, the code compiles and links:

register_callback(reinterpret_cast<void*>(
    static_cast<void(*)(void*)>(my_callback<int>)), &value);

I’ve got no idea whether the cast is actually required and (if so) why GCC 4.5 allows me to leave it off, and then fails to instantiate the template. But at least I got the code to compile without resorting to hacks.

like image 98
Konrad Rudolph Avatar answered Sep 17 '22 16:09

Konrad Rudolph