I want to send a custom "Accept" header in my request when using urllib2.urlopen(..). How do I do that?
Simple urllib2 scripturlopen('http://python.org/') print "Response:", response # Get the URL. This gets the real URL. print "The URL is: ", response. geturl() # Getting the code print "This gets the code: ", response.
Finally, requests internally uses urllib3 , but it aims for an easier-to-use API. Great answer, now I have another reason to not use requests, and be more confident when using the new urllib .
request — Extensible library for opening URLs. Source code: Lib/urllib/request.py. The urllib. request module defines functions and classes which help in opening URLs (mostly HTTP) in a complex world — basic and digest authentication, redirections, cookies and more.
Not quite. Creating a Request
object does not actually send the request, and Request objects have no Read()
method. (Also: read()
is lowercase.) All you need to do is pass the Request
as the first argument to urlopen()
and that will give you your response.
import urllib2 request = urllib2.Request("http://www.google.com", headers={"Accept" : "text/html"}) contents = urllib2.urlopen(request).read()
I normally use:
import urllib2
request_headers = {
"Accept-Language": "en-US,en;q=0.5",
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64; rv:40.0) Gecko/20100101 Firefox/40.0",
"Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8",
"Referer": "http://thewebsite.com",
"Connection": "keep-alive"
}
request = urllib2.Request("https://thewebsite.com", headers=request_headers)
response = urllib2.urlopen(request).read()
print(response)
Beside the other solutions mentioned already, you could use add_header
method.
So the example provided py @pantsgolem will be:
import urllib2
request = urllib2.Request("http://www.google.com")
request.add_header('Accept','text/html')
##Show the header having the key 'Accept'
request.get_header('Accept')
response = urllib2.urlopen(request)
response.read()
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