I want to create a form given its class name as a string, which has been asked about before, but instead of calling GetClass
, I want to use Delphi's new RTTI feature.
With this code, I've got a TRttiType
, but I don't know how to instantiate it.
var
f:TFormBase;
ctx:TRttiContext;
lType:TRttiType;
begin
ctx := TRttiContext.Create;
for lType in ctx.GetTypes do
begin
if lType.Name = 'TFormFormulirPendaftaran' then
begin
//how to instantiate lType here?
Break;
end;
end;
end;
I've also tried lType.NewInstance
with no luck.
You must cast the TRttiType
to the TRttiInstanceType
class and then invoke the constructor using the GetMethod
function.
Try this sample
var
ctx:TRttiContext;
lType:TRttiType;
t : TRttiInstanceType;
f : TValue;
begin
ctx := TRttiContext.Create;
lType:= ctx.FindType('UnitName.TFormFormulirPendaftaran');
if lType<>nil then
begin
t:=lType.AsInstance;
f:= t.GetMethod('Create').Invoke(t.MetaclassType,[nil]);
t.GetMethod('Show').Invoke(f,[]);
end;
end;
You should use the TRttiContext.FindType()
method instead of manually looping through though the TRttiContext.GetTypes()
list, eg:
lType := ctx.FindType('ScopeName.UnitName.TFormFormulirPendaftaran');
if lType <> nil then
begin
...
end;
But either way, once you have located the TRttiType
for the desired class type, you can instantiate it like this:
type
TFormBaseClass = class of TFormBase;
f := TFormBaseClass(GetTypeData(lType.Handle)^.ClassType).Create(TheDesiredOwnerHere);
Or this, if TFormBase
is derived from TForm
:
f := TFormClass(GetTypeData(lType.Handle)^.ClassType).Create(TheDesiredOwnerHere);
Or this, if TFormBase
is derived from TCustomForm
:
f := TCustomFormClass(GetTypeData(lType.Handle)^.ClassType).Create(TheDesiredOwnerHere);
Update: Or, do it like @RRUZ showed. That is more TRttiType
-oriented, and doesn't rely on using functions from the older TypInfo
unit.
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