How can I get PyCharm to recognize a custom property decorator?

Question

Let's consider the following example class:

class Foo:
    def __init__(self):
        self._bar = None

    @property
    def bar(self):
        if self._bar is None:
            self._bar = ...  # a long computation
        return self._bar

I created a cachedproperty decorator to implicitly take care of storing the computed result as a member of the class instance. Here is a simplified example of such decorator class:

class cachedproperty(property):
    def __init__(self, fget):
        @functools.wraps(fget)
        def cfget(obj):
            name = '_' + fget.__name__
            if not hasattr(obj, name):
                setattr(obj, name, fget(obj))
            return getattr(obj, name)
        super().__init__(cfget)

And now class Foo looks like this:

class Foo:
    @cachedproperty
    def bar(self):
        return ...  # a long computation

Even though it works, it is somewhat inconvenient that PyCharm now fails to treat bar as a property of Foo, and instead treats it as a method. This can be witnessed, for example, in the autocompletion dropdown:

My question is: how can I force PyCharm to treat my custom property decorator as an actual property?

Answer 1

It would appear that PyCharm makes this decision purely based on the name of the decorator. For example, renaming your cachedproperty decorator to cached_property (so that it matches Django's decorator of that name) works:

… whereas using the builtin property decorator with a different name doesn't: