You can group month and year with the help of function DATE_FORMAT() in MySQL. The GROUP BY clause is also used.
Group By Month Name In the above SQL query we use date_format(order_date, “%M”) to convert a date column into month name, and use sum column to add up the sales amounts.
The MySQL GROUP BY Statement The GROUP BY statement groups rows that have the same values into summary rows, like "find the number of customers in each country". The GROUP BY statement is often used with aggregate functions ( COUNT() , MAX() , MIN() , SUM() , AVG() ) to group the result-set by one or more columns.
GROUP BY YEAR(t.summaryDateTime), MONTH(t.summaryDateTime);
is what you want.
GROUP BY DATE_FORMAT(summaryDateTime,'%Y-%m')
I prefer
SELECT
MONTHNAME(t.summaryDateTime) as month, YEAR(t.summaryDateTime) as year
FROM
trading_summary t
GROUP BY EXTRACT(YEAR_MONTH FROM t.summaryDateTime);
SELECT MONTHNAME(t.summaryDateTime) as month, YEAR(t.summaryDateTime) as year
FROM trading_summary t
GROUP BY YEAR(t.summaryDateTime) DESC, MONTH(t.summaryDateTime) DESC
Should use DESC for both YEAR and Month to get correct order.
I know this is an old question, but the following should work if you don't need the month name at the DB level:
SELECT EXTRACT(YEAR_MONTH FROM summaryDateTime) summary_year_month
FROM trading_summary
GROUP BY summary_year_month;
See EXTRACT function docs
You will probably find this to be better performing.. and if you are building a JSON object in the application layer, you can do the formatting/ordering as you run through the results.
N.B. I wasn't aware you could add DESC to a GROUP BY clause in MySQL, perhaps you are missing an ORDER BY clause:
SELECT EXTRACT(YEAR_MONTH FROM summaryDateTime) summary_year_month
FROM trading_summary
GROUP BY summary_year_month
ORDER BY summary_year_month DESC;
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