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T-SQL datetime rounded to nearest minute and nearest hours with using functions

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How do you round datetime in SQL?

Rounding or truncating timestamps are especially useful when you're grouping by time. If you are rounding by year, you can use the corresponding function: select year(getdate()) as 'Year'; Be careful if you are grouping by months or smaller timestamp fragments (weeks, days, hours, minutes).

What are the date functions in SQL?

SQL Date Data TypesDATE - format YYYY-MM-DD. DATETIME - format: YYYY-MM-DD HH:MI:SS. TIMESTAMP - format: YYYY-MM-DD HH:MI:SS. YEAR - format YYYY or YY.

How can I add hours and minutes in SQL Server?

For your calculation to work you would need 23.983333333*60. I would suggest using for ultimate accuracy (23*60)+59 = 1439. Making the final query "SELECT DATEADD(MINUTE, 1439, CAST('2016-07-08' AS DATETIME))".


declare @dt datetime

set @dt = '09-22-2007 15:07:38.850'

select dateadd(mi, datediff(mi, 0, @dt), 0)
select dateadd(hour, datediff(hour, 0, @dt), 0)

will return

2007-09-22 15:07:00.000
2007-09-22 15:00:00.000

The above just truncates the seconds and minutes, producing the results asked for in the question. As @OMG Ponies pointed out, if you want to round up/down, then you can add half a minute or half an hour respectively, then truncate:

select dateadd(mi, datediff(mi, 0, dateadd(s, 30, @dt)), 0)
select dateadd(hour, datediff(hour, 0, dateadd(mi, 30, @dt)), 0)

and you'll get:

2007-09-22 15:08:00.000
2007-09-22 15:00:00.000

Before the date data type was added in SQL Server 2008, I would use the above method to truncate the time portion from a datetime to get only the date. The idea is to determine the number of days between the datetime in question and a fixed point in time (0, which implicitly casts to 1900-01-01 00:00:00.000):

declare @days int
set @days = datediff(day, 0, @dt)

and then add that number of days to the fixed point in time, which gives you the original date with the time set to 00:00:00.000:

select dateadd(day, @days, 0)

or more succinctly:

select dateadd(day, datediff(day, 0, @dt), 0)

Using a different datepart (e.g. hour, mi) will work accordingly.


"Rounded" down as in your example. This will return a varchar value of the date.

DECLARE @date As DateTime2
SET @date = '2007-09-22 15:07:38.850'

SELECT CONVERT(VARCHAR(16), @date, 120) --2007-09-22 15:07
SELECT CONVERT(VARCHAR(13), @date, 120) --2007-09-22 15

I realize this question is ancient and there is an accepted and an alternate answer. I also realize that my answer will only answer half of the question, but for anyone wanting to round to the nearest minute and still have a datetime compatible value using only a single function:

CAST(YourValueHere as smalldatetime);

For hours or seconds, use Jeff Ogata's answer (the accepted answer) above.