Avoid duplicates in INSERT INTO SELECT query in SQL Server

Question

Using NOT EXISTS:

INSERT INTO TABLE_2
  (id, name)
SELECT t1.id,
       t1.name
  FROM TABLE_1 t1
 WHERE NOT EXISTS(SELECT id
                    FROM TABLE_2 t2
                   WHERE t2.id = t1.id)

Using NOT IN:

INSERT INTO TABLE_2
  (id, name)
SELECT t1.id,
       t1.name
  FROM TABLE_1 t1
 WHERE t1.id NOT IN (SELECT id
                       FROM TABLE_2)

Using LEFT JOIN/IS NULL:

INSERT INTO TABLE_2
  (id, name)
   SELECT t1.id,
          t1.name
     FROM TABLE_1 t1
LEFT JOIN TABLE_2 t2 ON t2.id = t1.id
    WHERE t2.id IS NULL

Of the three options, the LEFT JOIN/IS NULL is less efficient. See this link for more details.

In MySQL you can do this:

INSERT IGNORE INTO Table2(Id, Name) SELECT Id, Name FROM Table1

Does SQL Server have anything similar?

I just had a similar problem, the DISTINCT keyword works magic:

INSERT INTO Table2(Id, Name) SELECT DISTINCT Id, Name FROM Table1

I was facing the same problem recently...
Heres what worked for me in MS SQL server 2017...
The primary key should be set on ID in table 2...
The columns and column properties should be the same of course between both tables. This will work the first time you run the below script. The duplicate ID in table 1, will not insert...

If you run it the second time, you will get a

Violation of PRIMARY KEY constraint error

This is the code:

Insert into Table_2
Select distinct *
from Table_1
where table_1.ID >1

Using ignore Duplicates on the unique index as suggested by IanC here was my solution for a similar issue, creating the index with the Option WITH IGNORE_DUP_KEY

In backward compatible syntax
, WITH IGNORE_DUP_KEY is equivalent to WITH IGNORE_DUP_KEY = ON.

Ref.: index_option