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I have a file where I want to grep for lines that start with either -rwx or drwx AND end in any number.
I've got this, but it isnt quite right. Any ideas?
grep [^.rwx]*[0-9] usrLog.txt 
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Matching the lines that end with a string : The $ regular expression pattern specifies the end of a line. This can be used in grep to match the lines which end with the given string or pattern. 11. -f file option Takes patterns from file, one per line.
GNU grep supports three regular expression syntaxes, Basic, Extended, and Perl-compatible. In its simplest form, when no regular expression type is given, grep interpret search patterns as basic regular expressions. To interpret the pattern as an extended regular expression, use the -E ( or --extended-regexp ) option.
You can use grep with -A n option to print N lines after matching lines. Using -B n option you can print N lines before matching lines. Using -C n option you can print N lines before and after matching lines.
The tricky part is a regex that includes a dash as one of the valid characters in a character class. The dash has to come immediately after the start for a (normal) character class and immediately after the caret for a negated character class. If you need a close square bracket too, then you need the close square bracket followed by the dash. Mercifully, you only need dash, hence the notation chosen.
grep '^[-d]rwx.*[0-9]$' "$@" See: Regular Expressions and grep for POSIX-standard details.
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