Generate random colors (RGB)

Question

I just picked up image processing in python this past week at the suggestion of a friend to generate patterns of random colors. I found this piece of script online that generates a wide array of different colors across the RGB spectrum.

def random_color():     levels = range(32,256,32)     return tuple(random.choice(levels) for _ in range(3)) 

I am simply interesting in appending this script to only generate one of three random colors. Preferably red, green, and blue.

Answer 1

A neat way to generate RGB triplets within the 256 (aka 8-byte) range is

color = list(np.random.choice(range(256), size=3))

color is now a list of size 3 with values in the range 0-255. You can save it in a list to record if the color has been generated before or no.

Answer 2

You could also use Hex Color Code,

Name    Hex Color Code  RGB Color Code Red     #FF0000         rgb(255, 0, 0) Maroon  #800000         rgb(128, 0, 0) Yellow  #FFFF00         rgb(255, 255, 0) Olive   #808000         rgb(128, 128, 0) 

For example

import matplotlib.pyplot as plt import random  number_of_colors = 8  color = ["#"+''.join([random.choice('0123456789ABCDEF') for j in range(6)])              for i in range(number_of_colors)] print(color) 

['#C7980A', '#F4651F', '#82D8A7', '#CC3A05', '#575E76', '#156943', '#0BD055', '#ACD338']

Lets try plotting them in a scatter plot

for i in range(number_of_colors):     plt.scatter(random.randint(0, 10), random.randint(0,10), c=color[i], s=200)  plt.show()