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Say I get a random number between 1 and 127. I change the number to binary and remove the 0b from it with the fallowing code:
key_one= int(raw_input("Enter key (0 <= key <= 127): ")) if key_one in range(128): bin_key_one=bin(key_one)[2:] print bin_key_one else: print "You have to enter key (0 <= key <= 127)" Now I want to make it 7-characters long by padding the beginning with zeros as necessary. I think I need to use a for loop, but can someone show me how to do it?
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Converting decimal integer to binary To convert integer to binary, start with the integer in question and divide it by 2 keeping notice of the quotient and the remainder. Continue dividing the quotient by 2 until you get a quotient of zero. Then just write out the remainders in the reverse order.
The length of a binary number is given by the value of n, actually it's n+1. For example, a binary number like 101 has a length of 3, something larger, like 10011110 has a length of 8.
An easy method of converting decimal to binary number equivalents is to write down the decimal number and to continually divide-by-2 (two) to give a result and a remainder of either a “1” or a “0” until the final result equals zero.
No you don't.
>>> '{0:07b}'.format(12) '0001100' So it happens that Python has a string method .zfill() for that:
>>> '1'.zfill(7) '0000001' >>> '10010'.zfill(7) '0010010' If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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