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I'm tooling around with Django and I'm wondering if there is a simple way to create a "back" link to the previous page using the template system.
I figure that in the worst case I can get this information from the request object in the view function, and pass it along to the template rendering method, but I'm hoping I can avoid all this boilerplate code somehow.
I've checked the Django template docs and I haven't seen anything that mentions this explicitly.
815
Just use the same label {% url 'index' %} . You may use each name in urls.py to link to the url. Show activity on this post. Create a new URL in the same format and give that name instead of index.
You can do that by using request. META['HTTP_REFERER'] , but it will exist if only your tab previous page was from your website, else there will be no HTTP_REFERER in META dict . So be careful and make sure that you are using . get() notation instead.
In Django, redirection is accomplished using the 'redirect' method. The 'redirect' method takes as argument: The URL you want to be redirected to as string A view's name. In the above example, first we imported redirect from django.
To reuse a Django template you use the Django built-in {% extends %} tag. The {% extends %} tag uses the syntax {% extends <name> %} to reuse the layout of another template. This means that in order to reuse the layout in listing 3-10 defined in a file base. html , you use the syntax {% extends "base.
Actually it's go(-1).
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