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Format a datetime into a string with milliseconds

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How do I get milliseconds from datetime?

To display the millisecond component of a DateTime valueParse(String) or DateTimeOffset. Parse(String) method. To extract the string representation of a time's millisecond component, call the date and time value's DateTime.

How do you represent milliseconds in a date format in Python?

strptime() function in python converts the string into DateTime objects. The strptime() is a class method that takes two arguments : string that should be converted to datetime object.

How do you display milliseconds in time format?

Usually we display time in in 12 hour format hh:mm:aa format (e.g. 12:30 PM) or 24 hour format HH:mm (e.g. 13:30), however sometimes we also want to show the milliseconds in the time. To show the milliseconds in the time we include “SSS” in the pattern which displays the Milliseconds.


To get a date string with milliseconds (3 decimal places behind seconds), use this:

from datetime import datetime

print datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S.%f')[:-3]

>>>> OUTPUT >>>>
2020-05-04 10:18:32.926

Note: For Python3, print requires parentheses:

print(datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S.%f')[:-3])

With Python 3.6 you can use:

from datetime import datetime
datetime.utcnow().isoformat(sep=' ', timespec='milliseconds')

Output:

'2019-05-10 09:08:53.155'

More info here: https://docs.python.org/3/library/datetime.html#datetime.datetime.isoformat


print datetime.utcnow().strftime('%Y%m%d%H%M%S%f')

http://docs.python.org/library/datetime.html#strftime-strptime-behavior


@Cabbi raised the issue that on some systems, the microseconds format %f may give "0", so it's not portable to simply chop off the last three characters.

The following code carefully formats a timestamp with milliseconds:

from datetime import datetime
(dt, micro) = datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S.%f').split('.')
dt = "%s.%03d" % (dt, int(micro) / 1000)
print dt

Example Output:

2016-02-26 04:37:53.133

To get the exact output that the OP wanted, we have to strip punctuation characters:

from datetime import datetime
(dt, micro) = datetime.utcnow().strftime('%Y%m%d%H%M%S.%f').split('.')
dt = "%s%03d" % (dt, int(micro) / 1000)
print dt

Example Output:

20160226043839901

Probably like this :

import datetime
now = datetime.datetime.now()
now.strftime('%Y/%m/%d %H:%M:%S.%f')[:-3]  
# [:-3] => Removing the 3 last characters as %f is for microsecs.

import datetime

# convert string into date time format.

str_date = '2016-10-06 15:14:54.322989'
d_date = datetime.datetime.strptime(str_date , '%Y-%m-%d %H:%M:%S.%f')
print(d_date)
print(type(d_date)) # check d_date type.


# convert date time to regular format.

reg_format_date = d_date.strftime("%d %B %Y %I:%M:%S %p")
print(reg_format_date)

# some other date formats.
reg_format_date = d_date.strftime("%Y-%m-%d %I:%M:%S %p")
print(reg_format_date)
reg_format_date = d_date.strftime("%Y-%m-%d %H:%M:%S")
print(reg_format_date)

<<<<<< OUTPUT >>>>>>>

2016-10-06 15:14:54.322989    
<class 'datetime.datetime'>    
06 October 2016 03:14:54 PM    
2016-10-06 03:14:54 PM    
2016-10-06 15:14:54