flask render_template with url parameter

Question

I use pdf.js to render pdf in web. The format of the target url like this:

http://www.example.com/book?file=abc.pdf

My problem is: I use flask template to generate page using:

return render_template('book.html', paraKey=paraValue)

But how to attach url parameter "file=abc.pdf" to url? The parameter will be read by viewer.js(included in book.html) that uses it to read file for rendering pdf.

I'm new to flask, hoping guys giving me some help!

Answer 1

You could use redirect function, which can redirect you whatever you want:

@app.route('/book')
def hello():
    file = request.args.get('file')
    if not file:
        return redirect("/?file=abc.pdf")
    return render_template('book.html', paraKey=paraValue)