As a simplified example, I tried to filter a Spark DataFrame with following code:
val xdf = sqlContext.createDataFrame(Seq(
("A", 1), ("B", 2), ("C", 3)
)).toDF("name", "cnt")
xdf.filter($"cnt" >1 || $"name" isin ("A","B")).show()
Then it errors:
org.apache.spark.sql.AnalysisException: cannot resolve '((cnt > 1) || name)' due to data type mismatch: differing types in '((cnt > 1) || name)' (boolean and string).;
What's the right way to do it? It seems to me that it stops reading after name
column. Is it a bug in the parser? I'm using Spark 1.5.1
val list = List("x","y","t")
xdf.filter($"column".isin(list: _*))
You have to parenthesize individual expressions:
xdf.filter(($"cnt" > 1) || ($"name" isin ("A","B"))).show()
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