Extract list of file names in a zip archive when `unzip -l`

Question

When I do unzip -l zipfilename, I see

1295627  08-22-11 07:10   A.pdf 473980  08-22-11 07:10   B.pdf ... 

I only want to see the filenames. I try this

unzip -l zipFilename | cut -f4 -d" " 

but I don't think the delimiter is just " ".

Answer 1

The easiest way to do this is to use the following command:

unzip -Z -1 archive.zip 

or

zipinfo -1 archive.zip 

This will list only the file names, one on each line.

The two commands are exactly equivalent. The -Z option tells unzip to treat the rest of the options as zipinfo options. See the man pages for unzip and zipinfo.

Answer 2

Assuming none of the files have spaces in names:

unzip -l filename.zip | awk '{print $NF}' 

My unzip output has both a header and footer, so the awk script becomes:

unzip -l filename.zip | awk '/-----/ {p = ++p % 2; next} p {print $NF}' 

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A version that handles filenames with spaces:

unzip -l filename.zip | awk '     /----/ {p = ++p % 2; next}     $NF == "Name" {pos = index($0,"Name")}     p {print substr($0,pos)} '