When joining data.frames along a key, and one key has a missing value (NA), my intuition was that rows with an NA key should have no match in the second data.frame. To my surprise, if there are NAs in both data.frames, dplyr matches them as if they were values.
This is extra confusing because this was discussed at length on the issues in the dplyr repository see here and it seems to be solved! If so, I'm not seeing how this is the correct solution ; or perhaps I'm missing something
I'm using dplyr 0.7.4
t1 <- data.frame(a = as.character(c("1", "2", NA, NA, "4", "2")), b = c(1, 2, 3, 3, 4, 5), stringsAsFactors = FALSE)
t2 <- data.frame(a = as.character(c("1", "2", NA)), c = c("b", "n", "i"), stringsAsFactors = FALSE)
library(dplyr)
t1
#> a b
#> 1 1 1
#> 2 2 2
#> 3 <NA> 3
#> 4 <NA> 3
#> 5 4 4
#> 6 2 5
t2
#> a c
#> 1 1 b
#> 2 2 n
#> 3 <NA> i
left_join(t1, t2, by = "a")
#> a b c
#> 1 1 1 b
#> 2 2 2 n
#> 3 <NA> 3 i
#> 4 <NA> 3 i
#> 5 4 4 <NA>
#> 6 2 5 n
When in fact I would have expected the following:
#> a b c
#> 1 1 1 b
#> 2 2 2 n
#> 3 <NA> 3 <NA>
#> 4 <NA> 3 <NA>
#> 5 4 4 <NA>
#> 6 2 5 n
The solution is to use the argument na_matches = "never"
. This was pointed out by Dani Rabaiotti and Hadley Wickham on twitter.
This argument is documented in the left_join
method for the tbl_df
class: ?left_join.tbl_df
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