Suppose, there is a reset
block with a single shift
:
val r = reset { // do smth. 1 shift {...} // do smth. 2 // do smth. 3 }
Is it correct that I place the shift
after "do smth. 2" or "do smth. 3" without changing the result r
? Is it correct that it does not matter where shift
stands in a reset
block?
It highly depends on what you are making within shift
. If you just calling provided function like this: shift((k: Unit => Unit) => k(Unit))
then, in your particular example, it really doesn't matter where shift
stands.
Shift
function just captures code that comes after it in other function (in my example this function is called k
). In other words, this code:
val r = reset {
// do smth. 1
shift((k: Unit => Unit) => k(Unit))
// do smth. 2
// do smth. 3
}
would be rewritten by compiler in something like this (this code just demonstrates general idea and it's not supposed to show what compiler plugin will actually generate):
val k = (Unit => Unit) => {
// do smth. 2
// do smth. 3
}
val r = {
// do smth. 1
k(Unit)
}
But if you have some logic inside shift
, like conditional k
execution, then it really matters where this shift
stands.
Hope this helps (and I hope, that I understood your question correctly)
Just adding to the answer already given, the place where you CAN move around shift
is whether to have code before the shift or have it inside the function you pass to shift
:
reset {
foo(); bar();
shift { k => stuff }
baz()
}
is the same as
reset {
foo();
shift { k => bar(); stuff }
baz()
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With