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convert seconds as double to std::chrono::duration?

Tags:

c++

c++11

chrono

I'm using c++11 <chrono> and have a number of seconds represented as a double. I want to use c++11 to sleep for this duration, but I cannot fathom how to convert it to a std::chrono::duration object that std::this_thread::sleep_for requires.

const double timeToSleep = GetTimeToSleep(); std::this_thread::sleep_for(std::chrono::seconds(timeToSleep));  // cannot convert from double to seconds 

I've locked at the <chrono> reference but I find it rather confusing.

Thanks

EDIT:

The following gives error:

std::chrono::duration<double> duration(timeToSleep ); std::this_thread::sleep_for(duration); 

the error:

c:\program files (x86)\microsoft visual studio 11.0\vc\include\chrono(749): error C2679: binary '+=' : no operator found which takes a right-hand operand of type 'const std::chrono::duration<double,std::ratio<0x01,0x01>>' (or there is no acceptable conversion) 2>          c:\program files (x86)\microsoft visual studio 11.0\vc\include\chrono(166): could be 'std::chrono::duration<__int64,std::nano> &std::chrono::duration<__int64,std::nano>::operator +=(const std::chrono::duration<__int64,std::nano> &)' 2>          while trying to match the argument list '(std::chrono::nanoseconds, const std::chrono::duration<double,std::ratio<0x01,0x01>>)' 2>          c:\program files (x86)\microsoft visual studio 11.0\vc\include\thread(164) : see reference to function template instantiation 'xtime std::_To_xtime<double,std::ratio<0x01,0x01>>(const std::chrono::duration<double,std::ratio<0x01,0x01>> &)' being compiled 2>          c:\users\johan\desktop\svn\jonsengine\jonsengine\src\window\glfw\glfwwindow.cpp(73) : see reference to function template instantiation 'void std::this_thread::sleep_for<double,std::ratio<0x01,0x01>>(const std::chrono::duration<double,std::ratio<0x01,0x01>> &)' being compiled 
like image 987
KaiserJohaan Avatar asked Jul 27 '13 15:07

KaiserJohaan


1 Answers

Don't do std::chrono::seconds(timeToSleep). You want something more like:

std::chrono::duration<double>(timeToSleep) 

Alternatively, if timeToSleep is not measured in seconds, you can pass a ratio as a template parameter to duration. See here (and the examples there) for more information.

like image 134
Cornstalks Avatar answered Sep 20 '22 12:09

Cornstalks