Or you can use tibble
's rownames_to_column
which does the same thing as David's answer:
library(tibble)
df <- tibble::rownames_to_column(df, "VALUE")
Note: The earlier function called add_rownames()
has been deprecated and is being replaced by tibble::rownames_to_column()
You can both remove row names and convert them to a column by reference (without reallocating memory using ->
) using setDT
and its keep.rownames = TRUE
argument from the data.table
package
library(data.table)
setDT(df, keep.rownames = TRUE)[]
# rn VALUE ABS_CALL DETECTION P.VALUE
# 1: 1 1007_s_at 957.7292 P 0.004862793
# 2: 2 1053_at 320.6327 P 0.031335632
# 3: 3 117_at 429.8423 P 0.017000453
# 4: 4 121_at 2395.7364 P 0.011447358
# 5: 5 1255_g_at 116.4936 A 0.397993682
# 6: 6 1294_at 739.9271 A 0.066864977
As mentioned by @snoram, you can give the new column any name you want, e.g. setDT(df, keep.rownames = "newname")
would add "newname" as the rows column.
A one line option is :
df$names <- rownames(df)
Alternatively, you can create a new dataframe (or overwrite the current one, as the example below) so you do not need to use of any external package. However this way may not be efficient with huge dataframes.
df <- data.frame(names = row.names(df), df)
Moved my comment into an answer per suggestion above:
You don't need extra packages, here's a one-liner:
d <- cbind(rownames(d), data.frame(d, row.names=NULL))
dplyr::as_tibble(df, rownames = "your_row_name")
will give you even simpler result.
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