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So " xx yy 11 22 33 " will become "xxyy112233". How can I achieve this?
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Remove spaces from std::string in C++ To remove this we will use the remove() function. With this remove() function it takes the beginning and end of the iterator, then takes the third argument that will be deleted from that iterator object.
Using Split() with Join() method To remove all whitespace characters from the string, use \s instead. That's all about removing all whitespace from a string in JavaScript.
Strip whitespace from the start and end of a C# string An easy way to do that is by calling C#'s Trim() method on the string: string example = " Hi there! "; string trimmed = example. Trim(); // Result: "Hi there!"
The strip() method is the most commonly accepted method to remove whitespaces in Python. It is a Python built-in function that trims a string by removing all leading and trailing whitespaces.
In general, we want a solution that is vectorised, so here's a better test example:
whitespace <- " \t\n\r\v\f" # space, tab, newline, # carriage return, vertical tab, form feed x <- c( " x y ", # spaces before, after and in between " \u2190 \u2192 ", # contains unicode chars paste0( # varied whitespace whitespace, "x", whitespace, "y", whitespace, collapse = "" ), NA # missing ) ## [1] " x y " ## [2] " ← → " ## [3] " \t\n\r\v\fx \t\n\r\v\fy \t\n\r\v\f" ## [4] NA gsub gsub replaces all instances of a string (fixed = TRUE) or regular expression (fixed = FALSE, the default) with another string. To remove all spaces, use:
gsub(" ", "", x, fixed = TRUE) ## [1] "xy" "←→" ## [3] "\t\n\r\v\fx\t\n\r\v\fy\t\n\r\v\f" NA As DWin noted, in this case fixed = TRUE isn't necessary but provides slightly better performance since matching a fixed string is faster than matching a regular expression.
If you want to remove all types of whitespace, use:
gsub("[[:space:]]", "", x) # note the double square brackets ## [1] "xy" "←→" "xy" NA gsub("\\s", "", x) # same; note the double backslash library(regex) gsub(space(), "", x) # same "[:space:]" is an R-specific regular expression group matching all space characters. \s is a language-independent regular-expression that does the same thing.
stringr approach: str_replace_all and str_trim stringr provides more human-readable wrappers around the base R functions (though as of Dec 2014, the development version has a branch built on top of stringi, mentioned below). The equivalents of the above commands, using [str_replace_all][3], are:
library(stringr) str_replace_all(x, fixed(" "), "") str_replace_all(x, space(), "") stringr also has a str_trim function which removes only leading and trailing whitespace.
str_trim(x) ## [1] "x y" "← →" "x \t\n\r\v\fy" NA str_trim(x, "left") ## [1] "x y " "← → " ## [3] "x \t\n\r\v\fy \t\n\r\v\f" NA str_trim(x, "right") ## [1] " x y" " ← →" ## [3] " \t\n\r\v\fx \t\n\r\v\fy" NA stringi approach: stri_replace_all_charclass and stri_trim stringi is built upon the platform-independent ICU library, and has an extensive set of string manipulation functions. The equivalents of the above are:
library(stringi) stri_replace_all_fixed(x, " ", "") stri_replace_all_charclass(x, "\\p{WHITE_SPACE}", "") Here "\\p{WHITE_SPACE}" is an alternate syntax for the set of Unicode code points considered to be whitespace, equivalent to "[[:space:]]", "\\s" and space(). For more complex regular expression replacements, there is also stri_replace_all_regex.
stringi also has trim functions.
stri_trim(x) stri_trim_both(x) # same stri_trim(x, "left") stri_trim_left(x) # same stri_trim(x, "right") stri_trim_right(x) # same I just learned about the "stringr" package to remove white space from the beginning and end of a string with str_trim( , side="both") but it also has a replacement function so that:
a <- " xx yy 11 22 33 " str_replace_all(string=a, pattern=" ", repl="") [1] "xxyy112233" If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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