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Convert a float64 to an int in Go

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go

People also ask

How do you round a float to an int?

round() method, which converts float to its nearest integer by adding +0.5 to it's value and then truncating it.

Can you convert a float to an int?

Since a float is bigger than int, you can convert a float to an int by simply down-casting it e.g. (int) 4.0f will give you integer 4. By the way, you must remember that typecasting just get rid of anything after the decimal point, they don't perform any rounding or flooring operation on the value.

How do I convert type in Golang?

Type conversion happens when we assign the value of one data type to another. Statically typed languages like C/C++, Java, provide the support for Implicit Type Conversion but Golang is different, as it doesn't support the Automatic Type Conversion or Implicit Type Conversion even if the data types are compatible.


package main
import "fmt"
func main() {
  var x float64 = 5.7
  var y int = int(x)
  fmt.Println(y)  // outputs "5"
}

Simply casting to an int truncates the float, which if your system internally represent 2.0 as 1.9999999999, you will not get what you expect. The various printf conversions deal with this and properly round the number when converting. So to get a more accurate value, the conversion is even more complicated than you might first expect:

package main

import (
    "fmt"
    "strconv"
)

func main() {
    floats := []float64{1.9999, 2.0001, 2.0}
    for _, f := range floats {
        t := int(f)
        s := fmt.Sprintf("%.0f", f)
        if i, err := strconv.Atoi(s); err == nil {
            fmt.Println(f, t, i)
        } else {
            fmt.Println(f, t, err)
        }
    }
}

Code on Go Playground


If its simply from float64 to int, this should work

package main

import (
    "fmt"
)

func main() {
    nf := []float64{-1.9999, -2.0001, -2.0, 0, 1.9999, 2.0001, 2.0}

    //round
    fmt.Printf("Round : ")
    for _, f := range nf {
        fmt.Printf("%d ", round(f))
    }
    fmt.Printf("\n")

    //rounddown ie. math.floor
    fmt.Printf("RoundD: ")
    for _, f := range nf {
        fmt.Printf("%d ", roundD(f))
    }
    fmt.Printf("\n")

    //roundup ie. math.ceil
    fmt.Printf("RoundU: ")
    for _, f := range nf {
        fmt.Printf("%d ", roundU(f)) 
    }
    fmt.Printf("\n")

}

func roundU(val float64) int {
    if val > 0 { return int(val+1.0) }
    return int(val)
}

func roundD(val float64) int {
    if val < 0 { return int(val-1.0) }
    return int(val)
}

func round(val float64) int {
    if val < 0 { return int(val-0.5) }
    return int(val+0.5)
}

Outputs:

Round : -2 -2 -2 0 2 2 2 
RoundD: -2 -3 -3 0 1 2 2 
RoundU: -1 -2 -2 0 2 3 3 

Here's the code in the playground - https://play.golang.org/p/HmFfM6Grqh


Correct rounding is likely desired.

Therefore math.Round() is your quick(!) friend. Approaches with fmt.Sprintf and strconv.Atois() were 2 orders of magnitude slower according to my tests with a matrix of float64 values that were intended to become correctly rounded int values.

package main
import (
    "fmt"
    "math"
)
func main() {
    var x float64 = 5.51
    var y float64 = 5.50
    var z float64 = 5.49
    fmt.Println(int(math.Round(x)))  // outputs "6"
    fmt.Println(int(math.Round(y)))  // outputs "6"
    fmt.Println(int(math.Round(z)))  // outputs "5"
}

math.Round() does return a float64 value but with int() applied afterwards, I couldn't find any mismatches so far.


You can use int() function to convert float64 type data to an int. Similarly you can use float64()

Example:

func check(n int) bool { 
    // count the number of digits 
    var l int = countDigit(n)
    var dup int = n 
    var sum int = 0 

    // calculates the sum of digits 
    // raised to power 
    for dup > 0 { 
        **sum += int(math.Pow(float64(dup % 10), float64(l)))** 
        dup /= 10 
    } 

    return n == sum
}