I searched char*
to hex
string before but implementation I found adds some non-existent garbage at the end of hex
string. I receive packets from socket, and I need to convert them to hex
strings for log (null-terminated buffer). Can somebody advise me a good implementation for C++
?
Thanks!
Supposing data is a char*. Working example using std::hex:
for(int i=0; i<data_length; ++i)
std::cout << std::hex << (int)data[i];
Or if you want to keep it all in a string:
std::stringstream ss;
for(int i=0; i<data_length; ++i)
ss << std::hex << (int)data[i];
std::string mystr = ss.str();
Here is something:
char const hex_chars[16] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
for( int i = data; i < data_length; ++i )
{
char const byte = data[i];
string += hex_chars[ ( byte & 0xF0 ) >> 4 ];
string += hex_chars[ ( byte & 0x0F ) >> 0 ];
}
The simplest:
int main()
{
const char* str = "hello";
for (const char* p = str; *p; ++p)
{
printf("%02x", *p);
}
printf("\n");
return 0;
}
I've found good example here Display-char-as-Hexadecimal-String-in-C++:
std::vector<char> randomBytes(n);
file.read(&randomBytes[0], n);
// Displaying bytes: method 1
// --------------------------
for (auto& el : randomBytes)
std::cout << std::setfill('0') << std::setw(2) << std::hex << (0xff & (unsigned int)el);
std::cout << '\n';
// Displaying bytes: method 2
// --------------------------
for (auto& el : randomBytes)
printf("%02hhx", el);
std::cout << '\n';
return 0;
Method 1 as shown above is probably the more C++ way:
Cast to an unsigned int
Usestd::hex
to represent the value as hexadecimal digits
Usestd::setw
andstd::setfill
from<iomanip>
to format
Note that you need to mask the cast int against0xff
to display the least significant byte:(0xff & (unsigned int)el)
.Otherwise, if the highest bit is set the cast will result in the three most significant bytes being set to
ff
.
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