I have a NumPy array like:
a = np.arange(30)
I know that I can replace the values located at positions indices=[2,3,4]
using for instance fancy indexing:
a[indices] = 999
But how to replace the values at the positions that are not in indices
? Would be something like below?
a[ not in indices ] = 888
To remove an element from a NumPy array: Specify the index of the element to remove. Call the numpy. delete() function on the array for the given index.
In NumPy, to replace missing values NaN ( np. nan ) in ndarray with other numbers, use np. nan_to_num() or np. isnan() .
I don't know of a clean way to do something like this:
mask = np.ones(a.shape,dtype=bool) #np.ones_like(a,dtype=bool) mask[indices] = False a[~mask] = 999 a[mask] = 888
Of course, if you prefer to use the numpy data-type, you could use dtype=np.bool_
-- There won't be any difference in the output. it's just a matter of preference really.
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