Assume we have the following html:
<html> <body> <a href="/1234.html">TEXT A</a> <a href="/3243.html">TEXT B</a> <a href="/7445.html">TEXT C</a> <body> </html>
How do I make it find the element "a", which contains "TEXT A"?
So far I've got:
root = lxml.html.document_fromstring(the_html_above) e = root.find('.//a')
I've tried:
e = root.find('.//a[@text="TEXT A"]')
but that didn't work, as the "a" tags have no attribute "text".
Is there any way I can solve this in a similar fashion to what I've tried?
lxml. etree supports the simple path syntax of the find, findall and findtext methods on ElementTree and Element, as known from the original ElementTree library (ElementPath).
lxml provides a very simple and powerful API for parsing XML and HTML. It supports one-step parsing as well as step-by-step parsing using an event-driven API (currently only for XML).
lxml is a Python library which allows for easy handling of XML and HTML files, and can also be used for web scraping. There are a lot of off-the-shelf XML parsers out there, but for better results, developers sometimes prefer to write their own XML and HTML parsers.
You are very close. Use text()=
rather than @text
(which indicates an attribute).
e = root.xpath('.//a[text()="TEXT A"]')
Or, if you know only that the text contains "TEXT A",
e = root.xpath('.//a[contains(text(),"TEXT A")]')
Or, if you know only that text starts with "TEXT A",
e = root.xpath('.//a[starts-with(text(),"TEXT A")]')
See the docs for more on the available string functions.
For example,
import lxml.html as LH text = '''\ <html> <body> <a href="/1234.html">TEXT A</a> <a href="/3243.html">TEXT B</a> <a href="/7445.html">TEXT C</a> <body> </html>''' root = LH.fromstring(text) e = root.xpath('.//a[text()="TEXT A"]') print(e)
yields
[<Element a at 0xb746d2cc>]
Another way that looks more straightforward to me:
results = [] root = lxml.hmtl.fromstring(the_html_above) for tag in root.iter(): if "TEXT A" in tag.text results.append(tag)
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