return value from python script to shell script

Question

I am new in Python. I am creating a Python script that returns a string "hello world." And I am creating a shell script. I am adding a call from the shell to a Python script.

1. i need to pass arguments from the shell to Python.
2. i need to print the value returned from Python in the shell script.

This is my code:

shellscript1.sh

#!/bin/bash # script for testing clear echo "............script started............" sleep 1 python python/pythonScript1.py exit 

pythonScript1.py

#!/usr/bin/python import sys  print "Starting python script!" try:     sys.exit('helloWorld1')  except:      sys.exit('helloWorld2')  

Answer 1

You can't return message as exit code, only numbers. In bash it can accessible via $?. Also you can use sys.argv to access code parameters:

import sys if sys.argv[1]=='hi':     print 'Salaam' sys.exit(0) 

in shell:

#!/bin/bash # script for tesing clear echo "............script started............" sleep 1 result=`python python/pythonScript1.py "hi"` if [ "$result" == "Salaam" ]; then     echo "script return correct response" fi 

Answer 2

Pass command line arguments to shell script to Python like this:

python script.py $1 $2 $3 

Print the return code like this:

echo $?