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At my 64bit Intel machine following code works:
mov rdi, 1 << 40
add r10, rdi
and this quite equivalent looking one produces a warning and doesn't work:
add r10, 1 << 40
Should I just stick with number 1 or am I missing something? This behaviour seems akward.
The warning produced by code nr 2:
warning: signed dword immediate exceeds bounds
666
x64 extends x86's 8 general-purpose registers to be 64-bit, and adds 8 new 64-bit registers. The 64-bit registers have names beginning with "r", so for example the 64-bit extension of eax is called rax. The new registers are named r8 through r15.
rax is the 64-bit, "long" size register. It was added in 2003 during the transition to 64-bit processors. eax is the 32-bit, "int" size register. It was added in 1985 during the transition to 32-bit processors with the 80386 CPU.
There is an opcode for mov r/m64, imm64, but there is no opcode for add r/m64, imm64 in the x86-64 instruction set. In other words: you cannot use 64-bit immediate operand for add, but you can for mov (there are many instructions that don't have the imm64 variant; you can check the Instruction Set Reference in the Intel Software Developer Manual to check which instructions have such variant and which don't).
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