Can const member function return a non-const pointer to a data member?

Question

Code goes first:

class A {     public:         ...         int *foo() const         {             return _px;         }     private:         int *_px; } 

The member function foo returns a non-const pointer to private member _px, which, I think, opens a door to modifying member _px, right?

Is foo a const member function? Should I add a const in front of the return type?

UPDATE

What a const-member-function should guarantee is that, it cannot change any data-member, right?

In my case, function foo doesn't open a door to modifying class As data-member _px, but a door to modifying what _px pointing to, So my question is, does this violate what a const-function should guarantee?

Answer 1

A const member function can only return a const pointer or reference to a member.

However, your example isn't returning a pointer to a member; it's returning a copy of a member that happens to be a pointer. That is allowed in a const member function (even if the pointer happens to point to another member).

This would not be allowed (note that it's now returning a reference):

int *& foo() const {return _px;} 

but this would (returning a const reference):

int * const & foo() const {return _px;} 

Answer 2

int *_px becomes int *const _px inside a const member function this implies that the pointer cannot be reseated but the data pointed to is still modifyable. Further your function returns a copy of the pointer so it does not matter anyways.