Angular form validation to validate the phone number

Question

I am trying to validate the phone number using regex expression in angular

HTML content

<div class="form-group row">
                <input type="text" class="form-control" appPhoneMask placeholder="Mobile Number" autocomplete="off"
                    [ngClass]="{ 'is-invalid': (f.inputCountryCode.errors && mobileNumberform.submitted) }"
                    formControlName="inputCountryCode">
                <div *ngIf="(f.inputCountryCode.invalid ) || (f.inputCountryCode.invalid && (f.inputCountryCode.dirty || f.inputCountryCode.touched))"
                    class="invalid-feedback">
                    <div *ngIf="f.inputCountryCode.errors.required">This field is required.</div>
                    <div *ngIf="f.inputCountryCode.errors.pattern">Invalid phone number.</div>
                </div>
            </div>

TS code

 this.$form = this.$builder.group({
      selectCountryCode: [null, Validators.required],
      inputCountryCode: [null, [Validators.required, Validators.pattern("[0-9 ]{12}")]]
    });

The validation pattern should allow numeric number with space because I am using the phone number masking which add space after 3 digits.

The pattern is not working keep getting phone numner validation false

Angular 4 Mobile number validation

Regex for field that allows numbers and spaces

Masking directive

export class PhoneMaskDirective {

  constructor(public ngControl: NgControl) { }

  @HostListener('ngModelChange', ['$event'])
  onModelChange(event) {
    this.onInputChange(event, false);
  }

  @HostListener('keydown.backspace', ['$event'])
  keydownBackspace(event) {
    this.onInputChange(event.target.value, true);
  }


  onInputChange(event, backspace) {
    let newVal = event.replace(/\D/g, '');
    if (backspace && newVal.length <= 6) {
      newVal = newVal.substring(0, newVal.length - 1);
    }
    if (newVal.length === 0) {
      newVal = '';
    } else if (newVal.length <= 3) {
      newVal = newVal.replace(/^(\d{0,3})/, '$1');
    } else if (newVal.length <= 6) {
      newVal = newVal.replace(/^(\d{0,3})(\d{0,3})/, '$1 $2');
    } else if (newVal.length <= 9) {
      newVal = newVal.replace(/^(\d{0,3})(\d{0,3})(\d{0,4})/, '$1 $2 $3');
    } else {
      newVal = newVal.substring(0, 10);
      newVal = newVal.replace(/^(\d{0,3})(\d{0,3})(\d{0,4})/, '$1 $2 $3');
    }
    this.ngControl.valueAccessor.writeValue(newVal);
  }
}

Answer 1

You can allow for:

• 9999 9999
• +61 2 9999 9999
• (02) 9999 9999

Validators.pattern('[- +()0-9]+')

Answer 2

Your regex expression requires 12 symbols of [0-9 ], while you input contains only 11.

Update your regexp for inputCountryCode to "[0-9 ]{11}":

 this.$form = this.$builder.group({
      selectCountryCode: [null, Validators.required],
      inputCountryCode: [null, [Validators.required, Validators.pattern("[0-9 ]{11}")]]
    });

Or you can add a space after phone number in input, so it will be 12 symbols.

But I would prefer to use more specific regexp for phone number like '[0-9]{3} [0-9]{3} [0-9]{3}', because with your pattern phone number 11 1111 111 or 111111 are valid numbers