I need to repeat async/await block several times, but cannot use the following code:
for (let i = 0; i <= 10; i += 1) {
const res = await DoSomething();
}
because it contradicts with no-await-in-loop rule.
Promise.all
if order of iteration doesn't matterIf you don't mind code running out-of-order (meaning order of each iteration doesn't matter), just use Promise.all
instead:
const promises = [];
for (let i = 0; i <= 10; i += 1) {
promises.push(DoSomething());
}
const responses = await Promise.all(promises);
From MDN:
The Promise.all(iterable) method returns a single Promise that resolves when all of the promises in the iterable argument have resolved
Otherwise if you do need to do sequential work just disable the rule for that block:
/* eslint-disable no-await-in-loop */
for (let i = 0; i <= 10; i += 1) {
const res = await DoSomething();
}
/* eslint-enable no-await-in-loop */
await
in a loop is most often than not, very inefficientThere is a reason that the rule exists. A lot of cases where await
is used in a loop are wasteful since each iteration is not dependent on the previous one, yet each iteration waits for the previous one to resolve before it even attempts to run the next one.
Promise.all
is more efficient in those cases since it does work in "parallel", more or less.
From ESLint no-await-in-loop docs:
Performing an operation on each element of an iterable is a common task. However, performing an await as part of each operation is an indication that the program is not taking full advantage of the parallelization benefits of async/await.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With