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I need to click on the below href element,which is present among similar href elements.
<a id="oldcontent" href="listDetails.do?camp=1865"><u>Re-Call</u></a>
Can anyone provide me xpath to click the above href link?Thanks in advance for help
420
This will get you the generic link: selenium. FindElement(By. XPath("xpath=//a[contains(@href,'listDetails.do')")).
Launch the Chrome browser and navigate to the URL or webpage. Hover the mouse over the desired element (object) on the web page, right-click on the element you are looking for XPath, and select “Inspect.”
Use the querySelector() method to get an element by an href attribute, e.g. document. querySelector('a[href="https://example.com"]') . The method returns the first element that matches the selector or null if no element with the provided selector exists in the DOM.
We can click a href link with Selenium webdriver. There are multiple ways to achieve this. First of all we need to identify the link with the help of the locators like link text and partial link text. The link text locator identifies the element whose text matches with text enclosed within the anchor tag.
Try below locator.
selenium.click("css=a[href*='listDetails.do'][id='oldcontent']");
or
selenium.click("xpath=//a[contains(@href,'listDetails.do') and @id='oldcontent']");
This works properly try this code-
selenium.click("xpath=//a[contains(@href,'listDetails.do') and @id='oldcontent']");
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