XCode 4.5 (4G182) + iPhone 5 iOS6 - Choose a destination with a supported architecture in order to run on this device

Question

So I have a brand new app I created last night for iOS6, using XCode 4.5. I can properly develop on my iPhone 4 with iOS6.

Today I got my new iPhone 5 with iOS6 and, after updating the certificates with the new device UUID, I tried to run my app on it and got this error:

XCode cannot run using the selected device. Choose a destination with a supported architecture in order to run on this device.

I've enabled the device for development. Both armv7 and armv7s are on the settings.

I have included the sources from the Facebook 3.0 SDK and the linker flag '-lsqlite3.0'. I'm guessing the issue has to be related, but cannot figure what is wrong.

Any ideas how to solve it?

PS: The issue happens too when running the app on the simulator. No idea what changed on my project or XCode between last night and today, other than I have a new device and new certificates.

The selected destination does not support the architecture for which the selected software is built. Switch to a destination that supports that architecture in order to run the selected software.

Answer 1

Also you need to select the compiler LLVM in

Project --> Build Settings --> Build Options

Answer 2

I have found the same issue while running an OLD project on XCode 5.0 and My solution is:

You need to do following steps for getting out with this:

1. Set Valid Architectures : armv7,armv7s

2. Set compiler as LLVM in Project ---> Build Settings ---> Build Options.

3. Set Base and Deployment sdk properly.

This is my solution. Happy To Help.

Answer 3

You need to add armv7s to your valid architectures under your Target's Build Settings.