Write a method
public static ArrayList merge(ArrayList a, ArrayList b)
that merges two array lists, alternating elements from both array lists. If one array list is shorter than the other, then alternate as long as you can and then append the remaining elemts from the longer array list. For example, if a is
1 4 9 16
and b is
9 7 4 9 11
then merge returns the array list
1 9 4 7 9 4 16 9 11
What I tried doing was writing a for loop with if statements such that a number is added to the merge array list from array list a when i is an even number (i%2==0) and from array list b when i is an odd number. I am however not sure how to deal with the fact that one array list can be longer than the other. Could anyone please help me out?
EDIT: Ok, here is the code (but it is far from correct):
public static ArrayList<Integer> merge(ArrayList<Integer> een, ArrayList<Integer> twee)
{
ArrayList<Integer> merged = new ArrayList<Integer>();
for(int i = 0; i<100; i++)
{
if(i%2!=0)
{
merged.add(a.get(i));
}
if(i%2 == 0)
{
merged.add(b.get(i));
}
}
System.out.println(merged);
return merged;
}
Iterators seem to do the trick most easily
public static <T> ArrayList<T> merge(Collection<T> a, Collection<T> b) {
Iterator<T> itA = a.iterator();
Iterator<T> itB = b.iterator();
ArrayList<T> result = new ArrayList<T>();
while (itA.hasNext() || itB.hasNext()) {
if (itA.hasNext()) result.add(itA.next());
if (itB.hasNext()) result.add(itB.next());
}
return result;
}
Without iterators:
public static <T> ArrayList<T> merge(List<T> a, List<T> b) {
ArrayList<T> result = new ArrayList<T>();
int size = Math.max(a.size(), b.size());
for (int i = 0; i < size; i++) {
if (i < a.size()) result.add(a.get(i));
if (i < b.size()) result.add(b.get(i));
}
return result;
}
Note, I've relaxed the method signature a bit. If you're implementing the merging using iterators, Collection
(or even Iterable
) will do. Otherwise, List
will do. There is no need to require ArrayList
as a method argument type
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