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wpf dictionary binding where key=variable

I have a test dictionary

MyDict = new Dictionary<string, Uri>
{
    {"First", new Uri("alma.jpg", UriKind.Relative)},
    {"Second", new Uri("korte.jpg", UriKind.Relative)}
};

and a simple XAML

<TextBlock Text="{Binding MyDict[First]}"
           FontSize="13" Width="200" Height="30" />

That shows perfectly the First key element Value

What I want is I have a string variable: DictKey Lets DictKey="First"

How to rewrite the XAML to use this variable

<TextBlock Text="{Binding MyDict[???DictKey????]}"
           FontSize="13" Width="200" Height="30" />

thx.

like image 497
KusziWorks Avatar asked Dec 10 '12 11:12

KusziWorks


1 Answers

I assume you have some property DictKey which holds the key of the item. You can use MultiBinding and set the first binding to your dictionary property and second binding to the property with the key of the item:

<TextBlock FontSize="13" Width="200" Height="30">
    <TextBlock.Text>
        <MultiBinding>
            <MultiBinding.Converter>
                <local:DictionaryItemConverter/>
            </MultiBinding.Converter>

            <Binding Path="MyDict"/>
            <Binding Path="DictKey"/>
        </MultiBinding>
    </TextBlock.Text>
</TextBlock>

The converter uses both values to read the item from dictionary:

public class DictionaryItemConverter : IMultiValueConverter
{
    public object Convert(object[] values, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        if (values != null && values.Length >= 2)
        {
            var myDict = values[0] as IDictionary;
            var myKey = values[1] as string;
            if (myDict != null && myKey != null)
            {
                //the automatic conversion from Uri to string doesn't work
                //return myDict[myKey];
                return myDict[myKey].ToString();
            }
        }
        return Binding.DoNothing;
    }

    public object[] ConvertBack(object value, Type[] targetTypes, object parameter, System.Globalization.CultureInfo culture)
    {
        throw new NotSupportedException();
    }
}
like image 183
Lubo Avatar answered Sep 23 '22 20:09

Lubo