I have a list view that displays a collection of items, each item has as its underlying data a view model (MVVM).
What I would like to do is display different menu items within the context menu when the user right clicks one of these list view items. The menu items displayed is dependent on the type of the item selected (i.e. the type of the underlying view model).
I would expect the below to work, but it does not (no items are displayed in the context menu).
<ListView.ContextMenu>
<ContextMenu DataContext="{Binding Path=PlacementTarget.SelectedItem, RelativeSource={RelativeSource Self}}">
<ContextMenu.Resources>
<DataTemplate DataType="{x:Type ViewModels:ViewModel1}">
<MenuItem Header="DoStuffForVM1" Command="{Binding DoStuffForVM1Command}"/>
</DataTemplate>
<DataTemplate DataType="{x:Type ViewModels:ViewModel2}">
<MenuItem Header="DoStuffForVM2" Command="{Binding DoStuffForVM2Command}"/>
</DataTemplate>
</ContextMenu.Resources>
<ContentPresenter ContentSource="{Binding}" />
</ContextMenu>
</ListView.ContextMenu>
Any ideas?
Thanks.
this works for me:
<ListView.ContextMenu>
<ContextMenu>
<ContentPresenter Content="{Binding Path=PlacementTarget.SelectedItem,
RelativeSource={RelativeSource AncestorType=ContextMenu}}" >
<ContentPresenter.Resources>
<DataTemplate DataType="{x:Type ViewModels:ViewModel1}">
<MenuItem Header="DoStuffForVM1" Command="{Binding DoStuffForVM1Command}"/>
</DataTemplate>
<DataTemplate DataType="{x:Type ViewModels:ViewModel2}">
<MenuItem Header="DoStuffForVM2" Command="{Binding DoStuffForVM2Command}"/>
</DataTemplate>
</ContentPresenter.Resources>
</ContentPresenter>
</ContextMenu>
</ListView.ContextMenu>
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