C:
# include <stdio.h>
main()
{
int i;
for (i=0; i<10; i++)
{
if (i>5)
{
i=i-1;
printf("%d",i);
}
}
}
Python:
for i in range(10):
if i>5: i=i-1
print(i)
When we compile C code, it goes into a infinite loop printing 5 forever, whereas in Python it doesn't, why not?
The Python output is:
0 1 2 3 4 5 5 6 7 8
In Python, the loop does not increment i
, instead it assigns it values from the iterable object (in this case, list). Therefore, changing i
inside the for loop does not "confuse" the loop, since in the next iteration i
will simply be assigned the next value.
In the code you provided, when i
is 6, it is then decremented in the loop so that it is changed to 5 and then printed. In the next iteration, Python simply sets it to the next value in the list [0,1,2,3,4,5,6,7,8,9]
, which is 7, and so on. The loop terminates when there are no more values to take.
Of course, the effect you get in the C loop you provided could still be achieved in Python. Since every for loop is a glorified while loop, in the sense that it could be converted like this:
for (init; condition; term) ...
Is equivalent to:
init
while(condition) {
...
term
}
Then your for infinite loop could be written in Python as:
i = 0
while i < 10:
if i > 5:
i -= 1
print i
i += 1
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