Function that finds how many times n can be divided in half

Question

Basically, I need a function that will divide n by two and return the number of times it can be done.

Coding so far:

def div(n):
    while n >= 0:
        n / 2
    return n

I know for a fact that I have to use the while loop, but I'm not confident in my third line of coding. What am I doing wrong?

Examples:

>>> div(4)
2
>>> div(7)
2

Answer 1

An integer n can be divided by 2: floor(log(n)/log(2)) times.

Answer 2

/ does not perform assignment. Since you're returning n and not changing its value, I'd think you should start there. Your other hints are = and %.