How to find the index where values in a list, increase value?

Question

I have a list that looks like:

mot = [0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,1,1,1,0,0,0]

I need to append to a list, the index when the element changes from 0 to 1 (and not from 1 to 0).

I've tried to do the following, but it also registers when it changes from 1 to 0.

i = 0 
while i != len(mot)-1:
    if mot[i] != mot[i+1]:
        mot_daily_index.append(i)
    i += 1

Also, but not as important, is there a cleaner implementation?

Answer 1

Here is how you can do that with a list comprehension:

mot = [0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,1,1,1,0,0,0]
mot_daily_index = [i for i,m in enumerate(mot) if i and m and not mot[i-1]]
print(mot_daily_index)

Output:

[7, 24]

Explanation:

• list(enumerate([7,5,9,3])) will return [(0, 7), (1, 5), (2, 9), (3, 3)], so the i in i for i, m in enumerate, is the index of m during that iteration.

Answer 2

Use a list comprehension with a filter to get your indexes:

mot = [0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,1,1,1,0,0,0]

idx = [i for i,v in enumerate(mot) if i and v > mot[i-1]]
print(idx)

Output:

[7, 24]