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Why must Java booleans be at least 1 byte in size?

It is known that C++ bools must be at least 1 byte in size so that pointers can be created for each [https://stackoverflow.com/a/2064565/7154924]. But there are no pointers to primitive types in Java. Yet, they still take up at least 1 byte [https://stackoverflow.com/a/383597/7154924].

Why is this the case - why can't Java booleans be 1 bit in size? Computation time aside, if one has a large boolean array, surely one could conceive a compiler that does the appropriate shifting to retrieve the individual bit corresponding to a boolean value?

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flow2k Avatar asked Dec 09 '17 20:12

flow2k


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1 Answers

There is no reason why a boolean must be one byte in size. In fact, is likely that booleans already aren't 1 byte in (effective) size in some scenarios: when packed next to other elements larger than 1 byte on the stack or in an object, they are likely to be larger (i.e., adding them to an object may cause the size to grow by more than one byte).

Any JVM is free to implement booleans as 1 bit, but as far as know none choose to do so, probably largely because:

  • Accessing one bit is often more expensive than accessing a byte, particularly when writing.

    To read a bit, a CPU using a "classic RISC" instruction set would often need need an additional and instruction to extract the relevant bit out of a packed byte (or larger word) of boolean bits. Some might even need a additional instruction to load a constant to and. In the case of indexing an array of boolean, where the bit-index isn't fixed at compile-time, you'd need a variable shift. Some CPUs such as x86 have an easier time since they have memory sourcetestinstructions, including specific bit-test instructions taking a variable position such asbt`. Such a CPU probably has similar read performance in both representations.

    Writing is worse: rather than a simple byte write to set a boolean value you now need to read the value, modify the appropriate bit and write it back. Some platforms such as x86 have memory source-and-destination RMW instructions such as and and or that will help, but these are still significantly more expensive than plain writes. In the worst case, repeatedly writing the same element will result in a dependency chain through memory that could slow your code down by an order of magnitude (a series of plain stores can't form a dependency chain).

    Even worse, the write method above is totally thread-unsafe. Two threads working on "independent" booleans might clobber each other, so the runtime would have to use atomic update operations just to write a bit for any field where the object cannot be proven local to the thread.

  • The space savings outside of arrays is usually very small, and is often zero: alignment concerns mean that a single bit will often end up taking the same space as a byte on the stack or in the layout for an object. Only if you had many primitive boolean values on the stack or an object would you see a savings (for example, objects are typically aligned to 8-byte boundaries, so if you have an object whose non-boolean fields are int or larger, you'd need at least 4 boolean values to save any space, and often you'd need 8).

  • This leaves the last remaining "big win" for bit-representation boolean in arrays of boolean, where you could have an asymptotic 8x space savings for large arrays. In fact, this case was motivating enough in the C++ world that vector<bool> there has a "special" implementation where each bool takes one bit - a never ending source of headaches due to all the required special cases and non-intuitive behavior (and often used as an example of a mis-feature that can't be removed now).

    If it weren't for the memory model I could imagine a world where Java implemented arrays of boolean in a bit-wise manner. They don't have the same issues as vector<bool> (mostly because of the extra layer of abtraction provided by the JIT and also because an array provides a simpler interface than vector) and it could be done efficiently, I think. There is that pesky memory model though. That model allows writes to different array elements to be safe if done by different threads (i.e,. they act as independent variables for the purpose of the memory model). All common CPUs support this directly if you implement boolean as a byte, since they have independent byte accesses. No CPUs offer independent bit-access though: you are stuck using atomic operations (x86 offers the lock bt* operations, but these are slow: other platforms have even worse options). That would destroy the performance of any boolean array implemented as a bit-array.

Finally, as described above, implementing boolean as a bit has significant downsides - but what about the upside?

As it turns out, if the user really wants this bit-packed representation of for boolean they can do so themselves! They can pack 8 boolean values into a byte (or 32 values into an int or whatever) in an object (and this is common for flags, etc) and the generated accessor code should be about efficient as efficient as if the JVM natively supported boolean-as-bit. In fact, when you know you want an array-of-bits representation for a large number of booleans, you can simply use BitSet - this has the representation you want and sidesteps the atomic issues by not offering any thread-safety guarantees. So by implementing boolean as a byte, you sidestep all the problems above, but still let the user "opt-in" to bit-level representation if they want, without much runtime penalty.

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BeeOnRope Avatar answered Sep 24 '22 08:09

BeeOnRope