Why is there only Math.floor(double)?
I have a float and I want to round it "down".
do I have to cast it to double?
In Python 2, floor(math. pi) returns a float value, whereas in Python 3, an int value is returned. In general, the Python 2 floor() function returns float values, whereas the Python 3 floor() function returns integer values.
floor() The Math. floor() function always rounds down and returns the largest integer less than or equal to a given number.
The Math. floor() function in JavaScript is used to round off the number passed as parameter to its nearest integer in Downward direction of rounding i.g towards the lesser value. Hence, math. floor(3.6) = 3.
It will be converted automatically (see this on widening primitive conversions). If you want the result as a float
, however, you will need to explicitly cast the return value.
Yes, but when speed is critical support for single precision floats should be provided. There should be a single precision analogous for java.lang.Math
No, a float
primitive will automatically be cast to a double
without the loss of any precision.
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