Below is some code to use SDL with Haskell to draw a diagonal line. I get a CYAN line when the RGB clearly should be white. This is on Ubuntu. Am I doing something wrong?
import qualified Graphics.UI.SDL as SDL
import qualified Graphics.UI.SDL.Primitives as SDLP
main = do
SDL.init [SDL.InitEverything]
SDL.setVideoMode 640 480 32 []
SDL.setCaption "My Window" "My Test"
surf0 <- SDL.getVideoSurface
white <- SDL.mapRGB (SDL.surfaceGetPixelFormat surf0) 255 255 255
SDLP.line surf0 0 0 640 480 white
SDL.flip surf0
eventLoop
SDL.quit
print "done"
where
eventLoop = SDL.waitEventBlocking >>= checkEvent
checkEvent (SDL.KeyUp _) = return ()
checkEvent _ = eventLoop
Maybe a less dirty hack (though probably platform/implementation dependant) :
import GHC.Word
import Data.Bits
fi a = fromIntegral a
rgbColor::Word8→ Word8→ Word8→ Pixel
rgbColor r g b = Pixel (shiftL (fi r) 24 .|. shiftL (fi g) 16 .|. shiftL (fi b) 8 .|. (fi 255))
I observe the same effect on Lucid with ATI HD2400 and radeon driver (if that matters). But there is a workaround.
This example draws a white line:
import qualified Graphics.UI.SDL as SDL
import qualified Graphics.UI.SDL.Primitives as SDLP
import Control.Applicative ((<$>))
main = do
SDL.init [SDL.InitEverything]
sbase <- SDL.setVideoMode 640 480 24 [] -- draw here
-- an ugly hack to get pixel format from an RGB surface:
rgbPF <- SDL.surfaceGetPixelFormat <$> SDL.createRGBSurfaceEndian [] 1 1 24
white <- SDL.mapRGB rgbPF (-1) (-1) (-1)
SDLP.line sbase 0 0 (640-1) (480-1) white
SDL.flip sbase
eventLoop
SDL.quit
where
eventLoop = SDL.waitEventBlocking >>= checkEvent
checkEvent (SDL.KeyDown _) = return ()
checkEvent _ = eventLoop
I accept that this is an ugly hack, but it seems that default surface' pixel format is not RGB (?), and using a pixel format of a surface known to be RGB helps. I don't have experience with SDL, so I cannot tell what the right way to use it is.
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