I have the following simple code:
import urllib2
import sys
sys.path.append('../BeautifulSoup/BeautifulSoup-3.1.0.1')
from BeautifulSoup import *
page='http://en.wikipedia.org/wiki/Main_Page'
c=urllib2.urlopen(page)
This code generates the following error messages:
c=urllib2.urlopen(page)
File "/usr/lib64/python2.4/urllib2.py", line 130, in urlopen
return _opener.open(url, data)
File "/usr/lib64/python2.4/urllib2.py", line 364, in open
response = meth(req, response)
File "/usr/lib64/python2.4/urllib2.py", line 471, in http_response
response = self.parent.error(
File "/usr/lib64/python2.4/urllib2.py", line 402, in error
return self._call_chain(*args)
File "/usr/lib64/python2.4/urllib2.py", line 337, in _call_chain
result = func(*args)
File "/usr/lib64/python2.4/urllib2.py", line 480, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
But if I replace urllib2 by urllib, I get no error messages. Can anybody explain this behavior?
The original urllib
simply does not raise an exception on a 403 code. If you add print c.getcode()
to the last line of your program, urllib
will reach it and still print out 403.
Then if you do print c.read()
at the end, you will see that you did indeed get an error page from Wikipedia. It's just a matter of urllib2
deciding to treat an error 403 as a runtime exception, versus urllib
allowing you to still get an error 403 and then do something with the page.
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