C++17 to add hexadecimal floating constant (floating point literal). Why? How about a couple of examples showing the benefits.
A "floating-point constant" is a decimal number that represents a signed real number. The representation of a signed real number includes an integer portion, a fractional portion, and an exponent. Use floating-point constants to represent floating-point values that can't be changed.
0x1. 999999999999ap-4 is an example of a normalized, double-precision hexadecimal floating-point constant; it represents the double-precision floating-point number nearest to the decimal number 0.1. The constant is made up of four parts: The prefix '0x', which shows it's a hexadecimal constant.
The floating-point constant is a double-precision floating-point number represented by two numbers separated by an E . The value of the constant is the product of the first number and the power of 10 specified by the second number.
Floating-point literals are numbers that have a decimal point or an exponential part. They can be represented as: Real literals. Binary floating-point literals. Hexadecimal floating-point literals (C only)
Floating point numbers are stored in x86/x64 processors in base 2, not base 10: https://en.wikipedia.org/wiki/Double-precision_floating-point_format . Because of that many decimal floating point numbers cannot be represented exactly, e.g decimal 0.1 could be represented as something like 0.1000000000000003 or 0.0999999999999997 - whatever has base 2 representation close enough to decimal 0.1 . Because of that inexactness, e.g. printing in decimal and then parsing of a floating-point number may result in a slightly different number than the one stored in memory binarily before printing.
For some application emergence of such errors is unacceptable: they want to parse into exactly the same binary floating-point number as the one which was before printing (e.g. one application exports floating-point data and another imports). For that, one could export and import doubles in hexadecimal format. Because 16 is a power of 2, binary floating-point numbers can be represented exactly in hexadecimal format.
printf
and scanf
have been extended with %a
format specifier which allows to print and parse hexadecimal floating point numbers. Though MSVC++ does not support %a
format specifier for scanf
yet:
The a and A specifiers (see printf Type Field Characters) are not available with scanf.
To print a double
in full precision with hexadecimal format one should specify printing of 13 hexadecimal digits after point, which correspond to 13*4=52 bits:
double x = 0.1;
printf("%.13a", x);
See more details on hexadecimal floating point with code and examples (note that at least for MSVC++ 2013 simple specification of %a
in printf
prints 6 hexadecimal digits after point, not 13 - this is stated in the end of the article).
Specifically for constants, as asked in the question, hexadecimal constants may be convenient for testing the application on exact hard-coded floating-point inputs. E.g. your bug may be reproducible for 0.1000000000000003, but not for 0.0999999999999997, so you need hexadecimal hardcoded value to specify the representation of interest for decimal 0.1 .
The main 2 reasons to use hex floats over decimals are accuracy and speed.
The algorithms for accurately converting between decimal constants and the underlying binary format of floating point numbers are surprisingly complicated, and even nowadays conversion errors still occasionally arise.
Converting between hexadecimal and binary is a much simpler endeavour, and guaranteed to be exact. An example use case is when it is critical that you use a specific floating point number, and not one either side (e.g. for implementations of special functions such as exp
). This simplicity also makes the conversion much faster (it doesn't require any intermediate "bignum" arithmetic): in some cases I've seen 3x speed up for read/write operations for hex float vs decimals.
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