Why does (= (vector nil) (vec nil)) return false?

Question

Is this just a quirk, or is there some fundamental concept that implies this?

Answer 1

vec converts into a vector(nil becomes an empty vector) while vector creates a vector with the given elements.

(vec nil) => []
(vector nil) => [nil]

you could have entered these expressions into a repl to see their results and why they're not equal.

Answer 2

user> (vec nil) ; => []

user> (vector nil) ; => [nil]

user> (= *1 *2) ; => false

Why should these be equal?