Just want to remove duplicates. Pool is vector<pair<string, int>>
but I seem to miss some elements at the start of the vector somehow. Can anyone verify the logic of the removal? Thanks :)
Pool Master::eliminateDuplicates(Pool generation)
{
for(int i = 0; i < generation.size(); i++)
{
string current = generation.at(i).first;
for(int j = i; j < generation.size(); j++)
{
if(j == i)
{
continue;
}
else
{
string temp = generation.at(j).first;
if(current.compare(temp) == 0)
{
Pool::iterator iter = generation.begin() + j;
generation.erase(iter);
}
}
}
}
return generation;
}
A vector element is removed with the vector erase member function. The syntax is: constexpr iterator erase(const_iterator position); The argument is an iterator that points to the element, to be removed.
We can remove duplicate element in an array by 2 ways: using temporary array or using separate index. To remove the duplicate element from array, the array must be in sorted order. If array is not sorted, you can sort it by calling Arrays. sort(arr) method.
vector::clear() clear() function is used to remove all the elements of the vector container, thus making it size 0.
If you don't mind sorting the vector, then you can use std::unique
. That would be O(Nlog(N))
#include <iostream>
#include <algorithm>
#include <vector>
int main()
{
std::vector<int> v{1,2,3,1,2,3,3,4,5,4,5,6,7};
std::sort(v.begin(), v.end());
auto last = std::unique(v.begin(), v.end());
v.erase(last, v.end());
for (const auto& i : v)
std::cout << i << " ";
std::cout << "\n";
}
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