How does a Java if statement work when it has an assignment and an equality check OR
-d together??
public static void test() { boolean test1 = true; if (test1 = false || test1 == false) { System.out.println("TRUE"); } else { System.out.println("FALSE"); } }
Why is this printing FALSE?
The expression is not parsed the way you think. It's not
(test1=false) || (test1 == false)
in which case the result would have been true
, but
test1 = (false || test1 == false)
The value of false || test1 == false
expression is computed first, and it is false
, because test1
is set to true
going into the computation.
The reason it is parsed this way is that the precedence of the ||
is lower than that of the ==
operator, but higher than the precedence of the assignment operator =
.
This is a precedence issue, basically. You're assuming that your code is equivalent to:
if ((test1 = false) || (test1 == false))
... but it's not. It's actually equivalent to:
if (test1 = (false || test1 == false))
... which is equivalent to:
if (test1 = (false || false))
(because test1
is true
to start with)
... which is equivalent to:
if (test1 = false)
which assigns the value false
to test1
, with the result of the expression being false
.
See the Java tutorial on operators for a useful table of operator precedence.
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