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Why does Scala evaluate the argument for a call-by-name parameter if the method is infix and right-associative?

As I understood call-by-name parameters of a method, the corresponding argument expression will not be evaluated when passing it to the method, but only when (and if) the value of the parameter is used in the method body.

In the following example, however, this is only true in the first two method calls, but not in the third one, although it should be a merely syntactical variation of the second case!?

Why is the argument expression evaluated in the third method call?

(I tested this code using Scala 2.11.7)

class Node(x: => Int)

class Foo {
  def :: (x: =>Int) = new Node(x)  // a right-associative method
  def !! (x: =>Int) = new Node(x)  // a left-associative method
}

// Infix method call will not evaluate a call-by-name parameter:
val node = (new Foo) !! {println(1); 1}
println("Nothing evaluated up to here")

// Right-associative method call will not evaluate a call-by-name parameter:
val node1 = (new Foo).::({println(1); 1})
println("Nothing evaluated up to here")

// Infix and right-associative method call will evaluate a call-by-name parameter - why??
val node2 = {println(1); 1} ::(new Foo)  // prints 1
println("1 has been evaluated now - why??")

Edit of 2020: Note that Scala 2.13 no longer shows this irritating behavior: val node2 = ... no longer prints anything.

like image 814
Holger Peine Avatar asked Nov 11 '15 17:11

Holger Peine


1 Answers

It's a bug. An old one, at that.

See SI-1980 and PR #2852.

The linked pull request added a compiler warning when using the -Xlint flag:

<console>:13: warning: by-name parameters will be evaluated eagerly when called as a right-associative infix operator. For more details, see SI-1980.
         def :: (x: =>Int) = new Node(x)  // a right-associative method
             ^
like image 121
Michael Zajac Avatar answered Sep 19 '22 12:09

Michael Zajac