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I have the code:
unsigned int length = strlen(somestring);
I'm compiling with the warning level on 4, and it's telling me that "conversion from size_t to unsigned int, possible loss of data" when a size_t is a typedef for an unsigned int.
Why!?
Edit:
I just solved my own problem. I'm an XP user, and my compiler was checking for 64 bit compatibility. Since size_t is platform dependent, for 64 bit it would be an unsigned long long, where that is not the same as an unsigned int.
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Yes, size_t is guaranteed to be an unsigned type.
On a typical 64-bit system, the size_t will be 64-bit, but unsigned int will be 32 bit. So we cannot use them interchangeably. One standard recommendation is that the size_t be at most as big as an unsigned long.
No. size_t can and does differ from unsigned int .
size_t is unsigned because negative sizes make no sense.
Because unsigned int is a narrower type on your machine than size_t. Most likely size_t is 64 bits wide, while unsigned int is 32 bits wide.
EDIT: size_t is not a typedef for unsigned int.
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