struct A
{
auto g1()
{
return true;
}
void f()
{
if (auto b = g1(); b) // ok
{
return;
}
if (auto b = g2(); b) // error: use of 'auto A::g2()' before deduction of 'auto'
{
return;
}
}
auto g2()
{
return true;
}
};
Why does C++17 if statement with initializer not work as expected?
Because the standard says so (quote from latest draft):
[dcl.spec.auto.general]
If a variable or function with an undeduced placeholder type is named by an expression ([basic.def.odr]), the program is ill-formed. Once a non-discarded return statement has been seen in a function, however, the return type deduced from that statement can be used in the rest of the function, including in other return statements.
[Example 4:
auto n = n; // error: n's initializer refers to n auto f(); void g() { &f; } // error: f's return type is unknown
To add a little bit of clarification, the "declaration" of g2
is "seen" because the definition of g1
is in the complete-class context. But that does not extend to having seen the definition of g2
.
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