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Why does BinaryReader.ReadUInt32() reverse the bit pattern?

I am trying to read a binary file with the BinaryReader class, and I need to read it in as blocks of UInt32, and then do some bit shifting etc. afterwords.

But, for some reason bit order is reversed when I use the ReadUInt32 method.

If I for example have a file where the first four bytes looks like this in hex, 0x12345678, they end up like this after being read by ReadUInt32: 0x78563412.

If I use the ReadBytes(4) method, I get the expected array:

[0x00000000]    0x12    byte
[0x00000001]    0x34    byte
[0x00000002]    0x56    byte
[0x00000003]    0x78    byte

Why is this? Is it just the way .net represents uints in memory? Is it the same across the different platforms (I am running 64bit Windows 7, .net 3.5 sp1)?

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Egil Hansen Avatar asked May 22 '09 18:05

Egil Hansen


4 Answers

Yes, this has to do with how your computer hardware stores uints in memory. It can be different across different platforms, although most desktop computers should be the same.

This is called endianness -- see wikipedia here:

http://en.wikipedia.org/wiki/Endian

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Clyde Avatar answered Dec 21 '22 23:12

Clyde


This seems to be an endianness issue. The docs say ReadUint32 reads in little-endian so the first byte is the least-significant so it goes to the lowest memory location. Your writer must be big-endian?

BinaryWriter.Write(UInt32) says it writes little-endian too. Is your binary data source not BinaryWriter?

Essentially what you need to do to fix it is this:

uint a = 0x12345678;
uint b = ((a & 0x000000FF) << 24) + ((a & 0x0000FF00) << 8) + ((a & 0x00FF0000) >> 8) + ((a & 0xFF000000) >> 24);

This shifts the least-significant byte up 24 bits, the 2nd LSB up 8 bits, the 3rd LSB down 8 bits, and the 4th LSB (the MSB) down 24 bits. Doing this is covered in several libraries.

Perhaps using BitConverter would be a bit more clear:

uint a = 0x12345678;
byte[] bytes = BitConverter.GetBytes(a);
// Swap byte order
uint b = BitConverter.ToUInt32(new byte[] { bytes[3], bytes[2], bytes[1], bytes[0] }, 0);
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Colin Burnett Avatar answered Dec 22 '22 01:12

Colin Burnett


Look into Jon Skeet's MiscUtil library for the Endian* classes, like EndianBinaryReader and EndianBitConverter.

http://www.yoda.arachsys.com/csharp/miscutil/

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bsneeze Avatar answered Dec 21 '22 23:12

bsneeze


Jon Skeet's written a BitConverter with configurable endian-ness. You might find it useful.

http://www.yoda.arachsys.com/csharp/miscutil/

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Michael Petrotta Avatar answered Dec 21 '22 23:12

Michael Petrotta