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Why does a method's `this` change when calling a reference to an object's method?

Tags:

javascript

function Person(gender) {
  this.gender = gender;
}

Person.prototype.sayGender = function()
{
  alert(this.gender);
};

var person1 = new Person('Male');
var genderTeller = person1.sayGender;

person1.sayGender(); // alerts 'Male'
genderTeller(); // alerts undefined

Why does genderTeller(); alerts undefined is not clear to me. if I see it I believe it's just same as line above it. Can some please explain the details

like image 658
sushil bharwani Avatar asked Oct 05 '11 06:10

sushil bharwani


2 Answers

When you assign a variable like this...

var genderTeller = person1.sayGender;

...you lose the context of the person1 object, and the function's this points to the global object (window in a browser), instead of the instantiated person1 object.

You get undefined because the gender property does not exist on window, and referencing an undefined property on an object returns undefined in JavaScript.

You can fix that in modern browsers with bind()...

var genderTeller = person1.sayGender.bind(person1);

...or jQuery has a method too called proxy().

var genderTeller = $.proxy(person1.sayGender, person1);
like image 83
alex Avatar answered Sep 28 '22 09:09

alex


This is how JavaScript scope works. I think the following example will give you a good insight.

this.gender = 'Female';

function Person(gender) {
  this.gender = gender;
}

Person.prototype.sayGender = function()
{
  alert(this.gender);
};

var person1 = new Person('Male');
var genderTeller = person1.sayGender;

person1.sayGender(); // alerts 'Male'
genderTeller(); // alerts 'Female'

There is a simple way of figuring out what is the value of this in a function you are calling. It is usually the object before the the dot where you invoked the function. For example:

person1.sayGender() here this = person1

object1.object2.foo() here this = object2

genderTeller() here this = window, because you are not calling it from any object.

Obviously you can set the value of this with .call or .apply function but usually I follow this rule when I build a mental model for my code.

like image 35
Rifat Avatar answered Sep 28 '22 08:09

Rifat